[SOLVED] \frac with \choose

How can one present fraction with combinations above and below?

For example, \frac{ 4\choose 4 48\choose 9 }{ 52\choose 13 } gives this:

I've already searched for "choose" in "Latex Help Forum".

Quote:

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Originally Posted by courteous

How can one present fraction with combinations above and below?

For example, \frac{ 4\choose 4 48\choose 9 }{ 52\choose 13 } gives this:

I've already searched for "choose" in "Latex Help Forum".

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I would use \binom{}{}
[tex]\frac{\displaystyle\binom{4}{4}\binom{48}{9}}{\dis playstyle\binom{52}{13}}[/tex]

Hello, courteous!

Quote:

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How can one present fraction with combinations above and below?

For example, \frac{ 4\choose 4 48\choose 9 }{ 52\choose 13 } gives this:

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The "choose" function must be enclosed in braces: .{6 \choose 2}


The code looks like this:

\frac{ {4\choose4} {48\choose9} } { {52\choose13} }

. . .



As Plato pointed out, it can be enlarged
. . by inserting \displaystyle in the numerator and denominator.


\frac{\displaystyle {4\choose4} {48\choose9} } {\displaystyle {52\choose13} }

. . .

It works!
Though I'm pretty sure I tried curly braces around \choose before. (Thinking)

Thank you both. (Happy)