
Originally Posted by
mlemilys
\begin{eqnarray}
\[\delta(x,y,z,\sigma,\xi, \zeta) & = & \frac{1}{(x-\sigma)(y-\xi)(z-\zeta)} \times \\
&& \hspace{-2cm} det\left( \begin{array}{cccc}
(x-1)^{2}+(y-2)^{2}+z^{2}-42.58 & (x-2)^{2}+y^{2}+(z-2)^{2}-106.49&(x-1)^{2}+(y-1)^{2}+(z-1)^{2}-14.22&(x-2)^{2}+(y-1)^{2}+z^{2}-42.58\\
(\sigma-1)^{2}+(y-2)^{2}+z^{2}-42.58 & (\sigma-2)^{2}+y^{2}+(z-2)^{2}-106.49&(\sigma-1)^{2}+(y-1)^{2}+(z-1)^{2}-14.22&(\sigma-2)^{2}+(y-1)^{2}+z^{2}-42.58\\
(\sigma-1)^{2}+(\xi-2)^{2}+z^{2}-42.58 & (\sigma-2)^{2}+\xi^{2}+(z-2)^{2}-106.49&(\sigma-1)^{2}+(\xi-1)^{2}+(z-1)^{2}-14.22&(\sigma-2)^{2}+(\xi-1)^{2}+z^{2}-42.58\\
(\sigma-1)^{2}+(\xi-2)^{2}+\zeta^{2}-42.58 & (\sigma-2)^{2}+\xi^{2}+(\zeta-2)^{2}-106.49&(\sigma-1)^{2}+(\xi-1)^{2}+(\zeta-1)^{2}-14.22&(\sigma-2)^{2}+(\xi-1)^{2}+\zeta^{2}-42.58\\
\end{array} \right) \]
\end{eqnarray}