# how to create def symbol?

• Oct 9th 2009, 06:58 PM
xvtstephen
how to create def symbol?
Please, help me define a math symbol for definition as shown in

Table of mathematical symbols - Wikipedia, the free encyclopedia

is defined as; equal by definition

it is the equal sign under a small font 'def'

the same symbol is also provided in OpenOffice math, but not in Latex.

Thank you all.
Stephen
• Oct 9th 2009, 07:17 PM
Prove It
Quote:

Originally Posted by xvtstephen
Please, help me define a math symbol for definition as shown in

Table of mathematical symbols - Wikipedia, the free encyclopedia

is defined as; equal by definition

it is the equal sign under a small font 'def'

the same symbol is also provided in OpenOffice math, but not in Latex.

Thank you all.
Stephen

Why not just use $:=$?
• Oct 9th 2009, 10:59 PM
CaptainBlack
Quote:

Originally Posted by xvtstephen
Please, help me define a math symbol for definition as shown in

Table of mathematical symbols - Wikipedia, the free encyclopedia

is defined as; equal by definition

it is the equal sign under a small font 'def'

the same symbol is also provided in OpenOffice math, but not in Latex.

Thank you all.
Stephen

You can define them:

\buildrel\triangle\over =

gives:

$\buildrel\triangle\over =$

and:

\buildrel d\over =

gives:

$\buildrel d\over =$

(we can't put "def" over "=" because our LaTeX always seems to throw an reserved word exception to any string starting def.

and of course \doteq gives $\doteq$

CB
• Oct 10th 2009, 12:10 AM
flyingsquirrel
Quote:

Originally Posted by CaptainBlack
\buildrel\triangle\over =

gives:

$\buildrel\triangle\over =$

\triangleq : $\triangleq$
• Oct 10th 2009, 12:42 AM
Opalg
Quote:

Originally Posted by CaptainBlack
\buildrel d\over =

gives:

$\buildrel d\over =$

(we can't put "def" over "=" because our LaTeX always seems to throw an reserved word exception to any string starting def.

You can fool the system into accepting a reserved word like def by disguising it, splitting it up with a pair of braces.

$$\buildrel \text{d{}ef}\over =$$ produces $\buildrel \text{d{}ef}\over =$ .