having 2pi as the upper limit of an interval

**walleye** · October 7th 2009, 06:31 PM

i cant make this work
e.g.

$\int_0^2\pi \theta d\theta$

the pi is mean to be the upper limit of the integral, not inside the integrand
any helps?

also i cant find out how to do the inequality sign

**mr fantastic** · October 7th 2009, 06:44 PM

Originally Posted by walleye

i cant make this work
e.g.

$\int_0^2\pi \theta d\theta$

the pi is mean to be the upper limit of the integral, not inside the integrand
any helps?

also i cant find out how to do the inequality sign

Use braces ^{...}: [tex]\int_0^{2\pi} \theta d\theta[/tex] gives $\int_0^{2\pi} \theta d\theta$

What inequality sign: <, > $\geq$ , $\leq$ ....?

**walleye** · October 7th 2009, 06:50 PM

thankyou thankyou thankyou

hahaha "which inequality sign"
im sorry, its been a long day

i meant the .. = with a / thought it

**pickslides** · October 7th 2009, 06:56 PM

$\int_0^{2\pi} \theta d\theta$

\int_0^{2\pi} \theta d\theta

**walleye** · October 7th 2009, 08:00 PM

$2 \not= 3$

ahh here we go, i found it

**Prove It** · October 7th 2009, 08:48 PM

Originally Posted by pickslides

$\int_0^{2\pi} \theta d\theta$

\int_0^{2\pi} \theta d\theta

You should leave a small space in between the $\theta$ and the $d\theta$ .

\int_0^{2\pi} \theta \, d\theta

gives

$\int_0^{2\pi} \theta \, d\theta$

**walleye** · October 7th 2009, 09:14 PM

new question sports stars

how do you do the multiplication sign?
haha sorry if these questions are annoyingly basic, but i figure you might be able to answer before i find it in a guide some where

**walleye** · October 7th 2009, 09:18 PM

$5 \times 3 \not= 14$

im learning

**mr fantastic** · October 7th 2009, 09:20 PM

Originally Posted by walleye

new question sports stars

how do you do the multiplication sign?
haha sorry if these questions are annoyingly basic, but i figure you might be able to answer before i find it in a guide some where

Read this: LaTeX Symbols

**pickslides** · October 8th 2009, 01:01 PM

Originally Posted by Prove It

You should leave a small space in between the $\theta$ and the $d\theta$ .

\int_0^{2\pi} \theta \, d\theta

gives

$\int_0^{2\pi} \theta \, d\theta$

Good point, I like to write it like this

\int_0^{2\pi} \theta~d\theta

$\int_0^{2\pi} \theta~d\theta$

**pickslides** · October 8th 2009, 01:03 PM

Originally Posted by walleye

$5 \times 3 \not= 14$

im learning

Also you can consider \neq

$<br /> \neq<br />$

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