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Math Help - having 2pi as the upper limit of an interval

  1. #1
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    having 2pi as the upper limit of an interval

    i cant make this work
    e.g.

    \int_0^2\pi \theta d\theta

    the pi is mean to be the upper limit of the integral, not inside the integrand
    any helps?


    also i cant find out how to do the inequality sign
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  2. #2
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    Quote Originally Posted by walleye View Post
    i cant make this work
    e.g.

    \int_0^2\pi \theta d\theta

    the pi is mean to be the upper limit of the integral, not inside the integrand
    any helps?


    also i cant find out how to do the inequality sign
    Use braces ^{...}: [tex]\int_0^{2\pi} \theta d\theta[/tex] gives \int_0^{2\pi} \theta d\theta

    What inequality sign: <, > \geq, \leq ....?
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  3. #3
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    thankyou thankyou thankyou

    hahaha "which inequality sign"
    im sorry, its been a long day

    i meant the .. = with a / thought it
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  4. #4
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    \int_0^{2\pi} \theta d\theta

    \int_0^{2\pi} \theta d\theta
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  5. #5
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    2 \not= 3

    ahh here we go, i found it
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  6. #6
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    Quote Originally Posted by pickslides View Post
    \int_0^{2\pi} \theta d\theta

    \int_0^{2\pi} \theta d\theta
    You should leave a small space in between the \theta and the d\theta.

    \int_0^{2\pi} \theta \, d\theta

    gives

    \int_0^{2\pi} \theta \, d\theta
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  7. #7
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    new question sports stars

    how do you do the multiplication sign?
    haha sorry if these questions are annoyingly basic, but i figure you might be able to answer before i find it in a guide some where
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  8. #8
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    5 \times 3 \not= 14

    im learning
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  9. #9
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    Quote Originally Posted by walleye View Post
    new question sports stars

    how do you do the multiplication sign?
    haha sorry if these questions are annoyingly basic, but i figure you might be able to answer before i find it in a guide some where
    Read this: LaTeX Symbols
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  10. #10
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    Quote Originally Posted by Prove It View Post
    You should leave a small space in between the \theta and the d\theta.

    \int_0^{2\pi} \theta \, d\theta

    gives

    \int_0^{2\pi} \theta \, d\theta
    Good point, I like to write it like this

    \int_0^{2\pi} \theta~d\theta

    \int_0^{2\pi} \theta~d\theta
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  11. #11
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    Quote Originally Posted by walleye View Post
    5 \times 3 \not= 14

    im learning

    Also you can consider \neq

     <br />
\neq<br />
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