# Making something appear below center

• Sep 23rd 2009, 06:02 PM
redsoxfan325
Making something appear below center
$\frac{\displaystyle\frac{{\color{red}P^x}~\display style\frac{\Gamma}{(P\Rightarrow Q)}}{Q}~\displaystyle\frac{\Gamma}{(Q\Rightarrow R)}}{\displaystyle\frac{R}{(P\Rightarrow R)}~x}$

Is there any way to push down that $P^x$ so that it's sitting right on top of the line (while keeping everything else the same)?

Thanks.
• Oct 10th 2009, 06:34 AM
Stefan_K
vertical alignment in fractions
A quick workaround using \llap:

$\frac{\displaystyle\frac{\qquad\displaystyle\frac{ \Gamma}{\llap{\color{red}P^x~}(P\Rightarrow Q)}}{Q}~
\displaystyle\frac{\Gamma}{(Q\Rightarrow R)}}{\displaystyle\frac{R}{(P\Rightarrow R)}~x}$

Stefan
• Oct 10th 2009, 08:45 AM
redsoxfan325
Quote:

Originally Posted by Stefan_K
A quick workaround using \llap:

$\frac{\displaystyle\frac{\qquad\displaystyle\frac{ \Gamma}{\llap{\color{red}P^x~}(P\Rightarrow Q)}}{Q}~
\displaystyle\frac{\Gamma}{(Q\Rightarrow R)}}{\displaystyle\frac{R}{(P\Rightarrow R)}~x}$

Stefan

One more question: what if I want to adjust something on the right. I tried qquad and rlap, but I got this:

$\frac{\displaystyle\frac{\Gamma}{(Q\Rightarrow P)\rlap{~~Q}}}{P}$
• Oct 10th 2009, 08:49 AM
Stefan_K
$\frac{\displaystyle\frac{\Gamma}{(Q\Rightarrow P)\rlap{~~Q}}\qquad}{P}$