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Math Help - i am testing the code

  1. #1
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    i am testing the code

    \vec{r}(t)= (-t+ 11/10)\vec{i}- 3t/vec{j}
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  2. #2
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    Hello, quah135791


    I assume you're hoping for:

    \vec{r}(t) \;=\;\left(-t + \tfrac{11}{10}\right)\vec{i} - 3t\vec{j}


    Click on QUOTE to see how it's done.

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  3. #3
    Junior Member
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    Quote Originally Posted by Soroban View Post
    Hello, quah135791


    I assume you're hoping for:

    \vec{r}(t) \;=\;\left(-t + \tfrac{11}{10}\right)\vec{i} - 3t\vec{j}


    Click on QUOTE to see how it's done.
    thanks!

    one more question, what is the code for the following those three equations
    x_1−x_2+x_3 = 2
    3x_1+x_2− x_3 = 2
    2x_1+x_2− x_3 = k
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  4. #4
    Grand Panjandrum
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    Quote Originally Posted by quah13579 View Post
    thanks!

    one more question, what is the code for the following those three equations
    x_1−x_2+x_3 = 2
    3x_1+x_2− x_3 = 2
    2x_1+x_2− x_3 = k
    There are lots of ways of doing this, the one I like (because it involves remembering fewer commands that some of the others) is:

    \begin{array}{rcrcrcr}<br />
x_1&-&x_2&+&x_3&=&2\\<br />
3x_1&+&x_2&-&x_3&=&2\\<br />
2x_1&+&x_2&-&x_3&=&k<br />
\end{array}

    Which is produced by:

    \begin{array}{rcrcrcr}
    x_1&-&x_2&+&x_3&=&2\\
    3x_1&+&x_2&-&x_3&=&2\\
    2x_1&+&x_2&-&x_3&=&k
    \end{array}

    CB
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