$\displaystyle \vec{r}(t)= (-t+ 11/10)\vec{i}- 3t/vec{j}$
There are lots of ways of doing this, the one I like (because it involves remembering fewer commands that some of the others) is:
$\displaystyle \begin{array}{rcrcrcr}
x_1&-&x_2&+&x_3&=&2\\
3x_1&+&x_2&-&x_3&=&2\\
2x_1&+&x_2&-&x_3&=&k
\end{array}$
Which is produced by:
\begin{array}{rcrcrcr}
x_1&-&x_2&+&x_3&=&2\\
3x_1&+&x_2&-&x_3&=&2\\
2x_1&+&x_2&-&x_3&=&k
\end{array}
CB