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Thread: Can anyone help me on this... im not confident with my answer :(

  1. #1
    rcs
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    Can anyone help me on this... im not confident with my answer :(

    Can anyone help me on this... im not confident with my answer :(-img.jpg

    a*a=a, a=0 -> 0*0=0, 0=0 true
    a*a=a, a=1 -> 1*1=1, 1=1 true

    Thank you
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  2. #2
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    Re: Can anyone help me on this... im not confident with my answer :(

    What you have shown is that 0 and 1 are possible solutions, not that they are the ONLY solutions. You must actually solve the equation.
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