I need to know if there is a way to solve:
v1 = a + d
v2 = a + j
v3 = g + d
v4 = g + j
With v1, v2, v3, v4 independent there are 4 unknowns. It appears the determinant is zero or sparse.
Thanks,
timeng
I have no idea what you mean here! Are the "four unknowns" a, d, g, and j? And $\displaystyle v_1$, $\displaystyle v_2$, $\displaystyle v_3$, and $\displaystyle v_4$ are constants? But what do you mean by "independent"? Are they vectors?
Yes, row-reducing leads to a matrix with last row all 0s. That gives $\displaystyle 0= v_1- v_2- v_3+ v_4$. If $\displaystyle v_1+ v_4$ is not equal to $\displaystyle v_2+ v_3$ then there is no solution. If $\displaystyle v_1+ v_4= v_2+ v_3$ then there are an infinite number of solutions.