find Z with $\displaystyle z^3 = \frac{1 + i}{\sqrt{2}}$

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- Apr 9th 2013, 04:44 AMblackinkHelp me solve this
find Z with $\displaystyle z^3 = \frac{1 + i}{\sqrt{2}}$

- Apr 9th 2013, 05:46 AMHallsofIvyRe: Help me solve this
Change to polar form, then use $\displaystyle \sqrt[3]{r(cos(\theta)+ i sin(\theta))}= r^{1/3}(cos(\theta/3)+ i sin(\theta/3))$