# Can someone please check my work in calculating this area?

• Aug 28th 2009, 01:34 PM
ineedhelp87
Can someone please check my work in calculating this area?
Okay, I needed to find the area of this figure: http://i25.tinypic.com/symtyt.jpg

So I figured out that each side had a total area of 224 (8*28), so the two combined would be 448, if they were separate. Since they overlap, I needed to subtract the area of the triangle from this. Using heron's formula, I plugged in the numbers: 1/2(14+14+8) --> square root of 18(18-14)(18-14)(18-8) --> square root of 18*4*4*10 --> square root of 2880. The square root of 2880 is 53.665.

So, I did 448-53.665=394. Is this correct?
• Aug 28th 2009, 02:12 PM
eXist
I disagree. The 2 parallelograms should have an area of 431.2 (7.7 * 28 * 2).

But you are right about subtracting the triangle. There is an easier way then using hero's formula.

Drop a height on the triangle and you have this:
http://img207.imageshack.us/img207/2382/86231316.png

Now use the Pythagorean theorem to calculate the height. Just easier in my opinion.
• Aug 28th 2009, 02:37 PM
ineedhelp87
Thank you so much!!