I have a few similar triangles problems. I'm really not sure how to do them. Could you please help me, or at least get me started on how to solve it.
Thank you very much!
Hello f1f2f3Sorry I haven't long to give you a complete answer, but since you said you are desperate, here's some help for the first two.Originally Posted by 354732
1)
Can you complete?
2) 's ABM, DEA are similar (Can you see why?)
AM = and
Can you complete?
Grandad
Hello again f1f2f3Number 3 is a bit more tricky, I think.
The easiest way is to use the formula , noting that , and . Then
But if you must use similar triangles...
Since , if we can prove that , then we're there. For then we should have .
So, in the diagram attached, is the foot of the perpendicular from to . We aim to prove that 's are similar, and hence that .
Let's assume that the length of the side of any of the squares is 1 unit. So (Pythag.)
Now 's are similar (Can you supply the reason?)
and
But
Therefore, since 's are similar, and hence .
Grandad