A bullet is fired into the air at an angle of 45 degrees. How long does it take to reach a height of 1000 feet

if the bullet is traveling at 2,828 ft per ser second? (Assume that the bullet travels in a straight line;

neglect the forces of gravity, and give your answer to the nearest foot)

OK, I got so far that the distance traveled was 1414 ft (this is a 45-45-90 triangle and the square root of 2 times 1000 gives you 1414 when you round). And I'm thinking this is a distace/rate/time problem simply now,

so wouldn't that mean 1414/2828 = .5? t=.5