1. ## Conic related.

I've just recently been introduced to conic sections and i need some help.

For the conic $\frac{x^2}{16}+\frac{y^2}{9}=1$ ,
how do i find the x-, y- intercepts, the coordinates of the foci, the length of the major axis, and the vertices. Also, how do i graph the conic?

How do i find these characteristics of this conic?

2. Originally Posted by crosser43
I've just recently been introduced to conic sections and i need some help.

For the conic $\frac{x^2}{16}+\frac{y^2}{9}=1$ ,
how do i find the x-, y- intercepts, the coordinates of the foci, the length of the major axis, and the vertices. Also, how do i graph the conic?

How do i find these characteristics of this conic?
Hi crosser43,

What you have here is the equation of an ellipse.

$\frac{x^2}{16}+\frac{y^2}{9}=1$

The general form is

$\frac{x^2}{a^2}+\frac{y^2}{b^2}=1$

The center of the ellipse is (0, 0).

The direction of the major axis is horizontal.

The length of the major axis is 2a.

The length of the minor axis is 2b.

An ellipse has two axes of symmetry which contain the major and minor axes. The lengths a, b, and c are related by the formula:

$c^2=a^2-b^2$

Using a = 4 and b = 3, find c.

The foci are at (-c, 0) and (c, 0).

The vertices of the major axis are at (-a, 0) and (a, 0). These are also your x-intercepts.

The vertices of the minor axis are at (0, b) and (0, -b).