Ok, I need help with my geometry homework. If anyone can thoroughly explain or something I'd appreciate it much.
"If the area of a trapezoid is 4x^2+4x+1 and one base is 2x+3 and the height is 2x+1, what is the length of the other base? Answers is in terms of x. "
Also I know that the area of a regular hexagon with a radius of 7 has an area of 127, but I've gotten down to 147 x sqrt(3) x 1/2. I know for sure that it's 127, I just don't know how to get 127 from there and have it in simplest radical form.
And... to find the area of an equilateral triangle with the sides of 5 cms.
If anyone can help.. i'd appreciate it.
Hello,
the area of a regular hexagon consists of 6 equilateral triangles. The side of this triangle is equal to r, in your case r = 7 cm.
Plug in r = 7 and you'll get: A = 127.3057...cm²
From the formula above you see that the area of an equilateral triangle with the side a is:
With a = 5 cm you'll get: A = 10.825... cm²
EB