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Math Help - Surface Area/Volume Problem: did i do it correctly?

  1. #1
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    Red face Surface Area/Volume Problem: did i do it correctly?

    Please check to see if i did this right. Thanks a trillion!

    A wooden shed in the shape os a rectangular prism with base length and width of 8' and 6' has a hieght of 10'. The shed is resting on the ground.

    a)What is the surface area of the shed that can be painted?

    SA=ph+2B (but you cant paint the part resting on the ground)
    SA=ph+B
    SA=300+48
    SA=348ft can be painted (is this squared? i dont think soo....)

    b) How many boxes with a volume of 6ft^3 can be stored in the shed?

    V=Bh
    V=48x10
    V=480ft^3
    480/6
    80 boxes with the volume of 6ft^3 can be stored in the shed
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  2. #2
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    Quote Originally Posted by sarahgasoline View Post
    Please check to see if i did this right. Thanks a trillion!

    A wooden shed in the shape os a rectangular prism with base length and width of 8' and 6' has a hieght of 10'. The shed is resting on the ground.

    a)What is the surface area of the shed that can be painted?

    SA=ph+2B (but you cant paint the part resting on the ground)
    SA=ph+B
    SA=300+48
    SA=348ft can be painted (is this squared? i dont think soo....)

    b) How many boxes with a volume of 6ft^3 can be stored in the shed?

    V=Bh
    V=48x10
    V=480ft^3
    480/6
    80 boxes with the volume of 6ft^3 can be stored in the shed
    a) p, the perimeter is 2 x 8 + 2 x 6 = 16 + 12 = 28 ft. So the surface area of the walls is 10 x 28 = 280 ft^2, not 300. (And yes, the unit is ft. - squared.)

    b) I don't like this question as it should depend on the dimensions of the boxes and not just their volume. However for the apparent spirit of the question this is done correctly.

    -Dan
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  3. #3
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    ha ha thanks. i always make mistakes on the easy parts
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