http://img187.imageshack.us/img187/4103/yesere.png

Confused here. Would CQF be 110 as well? Thus meaning that on the other side there exists 70 degrees?

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- July 26th 2009, 09:45 AMA Beautiful MindNo idea...transversal
http://img187.imageshack.us/img187/4103/yesere.png

Confused here. Would CQF be 110 as well? Thus meaning that on the other side there exists 70 degrees? - July 26th 2009, 10:04 AMred_dog
- July 26th 2009, 11:41 PMConorsmom
Yet another way to look at it : If AB is ll to CD, then angles APE and CQF are congruent, being 180 degrees as given.

This means that Angle CQF must be 70 degrees by the supplementary angle theorem.

This leaves the measurement of FQD to be 110 degrees, and being bisected by ray QR, means that the measurement of angle FQR is 55 degrees, 1/2 of FQD.

Now add m <FQR and m<CQF and you get A) 125 degrees.