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Math Help - Another area problem

  1. #1
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    Another area problem

    I am also having problems with this ...

    Last edited by mr fantastic; July 21st 2009 at 01:21 AM. Reason: Moved to new thread and edited accordingly
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  2. #2
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    Quote Originally Posted by KevinVM20 View Post
    I am also having problems with this ...

    This is just a simple application of the Pythagorean Theorem, a^2 + b^2 = c^2. In this case, a=12, and c=13. Solve for b. The area of the rectangle is then just a\cdot b.
    Last edited by mr fantastic; July 21st 2009 at 01:21 AM. Reason: Edited quote
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  3. #3
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    Quote Originally Posted by KevinVM20 View Post
    I am also having problems with this ...

    You are dealing with 2 congruent right triangles. Use Pythagorean theorem to get the length of the rectangle's width.

    Spoiler:

    Let w denote the length of the width. Then you have:

    13^2=w^2+12^2~\implies~w^2=25
    Last edited by mr fantastic; July 21st 2009 at 01:22 AM. Reason: Edited quote
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  4. #4
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    Thank you for your help. Your insight into the understanding of mathematical concepts is appreciated.

    Quote Originally Posted by earboth View Post
    You are dealing with 2 congruent right triangles. Use Pythagorean theorem to get the length of the rectangle's width.

    Spoiler:

    Let w denote the length of the width. Then you have:

    13^2=w^2+12^2~\implies~w^2=25
    Last edited by mr fantastic; July 21st 2009 at 01:23 AM.
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