# Thread: circle in the cartesian plane question. (coordinate geometry)

1. ## circle in the cartesian plane question. (coordinate geometry)

Find the equation of the circle which is tangential to the axis (2,0) and touches the line y=6

Unsure of workings?

Answers are; A, (x+2)^2 + (y-7)^2 = 26 B, 2x -y = 5 C, k = 0

Cheers Neils=)

Helle neils40

Welcome to Math Help Forum!
Originally Posted by neils40
Find the equation of the circle which is tangential to the axis (2,0) and touches the line y=6

Unsure of workings?

Answers are; A, (x+2)^2 + (y-7)^2 = 26 B, 2x -y = 5 C, k = 0

Cheers Neils=)
The question that you've given us here doesn't make sense, and the answers don't correspond in any way. Can we see the original question please?

3. Thanks Grandad. That was form my text book, looks like a missprint maybe... I will as my teacher.

4. Originally Posted by neils40
Find the equation of the circle which is tangential to the axis (2,0) and touches the line y=6
Do you mean "tangent to the x-axis at (2,0)"? (2,0) is a point not a line.
If so, then both given tangent lines are horizontal and the center of the circle is at (2, 3).

Unsure of workings?

Answers are; A, (x+2)^2 + (y-7)^2 = 26 B, 2x -y = 5 C, k = 0

Cheers Neils=)
There are no "A" or "B" in your question!

5. Hello, Neils!

Find the equation of the circle tangent to the x-axis at (2,0) and tangent to the line y=6

$\displaystyle (A);\;(x+2)^2 + (y-7)^2 \:=\:26\qquad (B)\;\;2x -y \:=\:5 \qquad (C)\;\;k \,=\, 0$

These are great answers . . . What were the questions?
Did you make a sketch?
Code:
          |
- - + - * * * - - - y=6
*           *
* |             *
*  |              *
|
*   |               *
*   |     o         *
*   |               *
|
*  |              *
* |             *
*           *
- - - + - * * * - - - - - -
|   (2,0)
|

Any idea where the center is and what the radius is?