Find the equation of the circle which is tangential to the axis (2,0) and touches the line y=6
Unsure of workings?
Answers are; A, (x+2)^2 + (y-7)^2 = 26 B, 2x -y = 5 C, k = 0
Cheers Neils=)
Do you mean "tangent to the x-axis at (2,0)"? (2,0) is a point not a line.
If so, then both given tangent lines are horizontal and the center of the circle is at (2, 3).
There are no "A" or "B" in your question!Unsure of workings?
Answers are; A, (x+2)^2 + (y-7)^2 = 26 B, 2x -y = 5 C, k = 0
Cheers Neils=)
Hello, Neils!
Did you make a sketch?Find the equation of the circle tangent to the x-axis at (2,0) and tangent to the line y=6
Answers are:
$\displaystyle (A);\;(x+2)^2 + (y-7)^2 \:=\:26\qquad (B)\;\;2x -y \:=\:5 \qquad (C)\;\;k \,=\, 0 $
These are great answers . . . What were the questions?Code:| - - + - * * * - - - y=6 * * * | * * | * | * | * * | o * * | * | * | * * | * * * - - - + - * * * - - - - - - | (2,0) |
Any idea where the center is and what the radius is?