Find the equation of the circle which is tangential to the axis (2,0) and touches the line y=6
Unsure of workings?
Answers are; A, (x+2)^2 + (y-7)^2 = 26 B, 2x -y = 5 C, k = 0
Cheers Neils=)
Find the equation of the circle which is tangential to the axis (2,0) and touches the line y=6
Unsure of workings?
Answers are; A, (x+2)^2 + (y-7)^2 = 26 B, 2x -y = 5 C, k = 0
Cheers Neils=)
Helle neils40
Welcome to Math Help Forum!The question that you've given us here doesn't make sense, and the answers don't correspond in any way. Can we see the original question please?Quote:
Originally Posted by neils40
Grandad
Thanks Grandad.(Happy) That was form my text book, looks like a missprint maybe... I will as my teacher.
Do you mean "tangent to the x-axis at (2,0)"? (2,0) is a point not a line.Quote:
Originally Posted by neils40
If so, then both given tangent lines are horizontal and the center of the circle is at (2, 3).
There are no "A" or "B" in your question!Quote:
Unsure of workings?
Answers are; A, (x+2)^2 + (y-7)^2 = 26 B, 2x -y = 5 C, k = 0
Cheers Neils=)
Hello, Neils!
Did you make a sketch?Quote:
Find the equation of the circle tangent to the x-axis at (2,0) and tangent to the line y=6
Answers are:
These are great answers . . . What were the questions?
Code:|
- - + - * * * - - - y=6
* *
* | *
* | *
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* | *
* | o *
* | *
|
* | *
* | *
* *
- - - + - * * * - - - - - -
| (2,0)
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Any idea where the center is and what the radius is?