# circle in the cartesian plane question. (coordinate geometry)

• July 20th 2009, 11:22 PM
neils40
circle in the cartesian plane question. (coordinate geometry)
Find the equation of the circle which is tangential to the axis (2,0) and touches the line y=6

Unsure of workings?

Answers are; A, (x+2)^2 + (y-7)^2 = 26 B, 2x -y = 5 C, k = 0

Cheers Neils=)
• July 21st 2009, 12:17 AM
Helle neils40

Welcome to Math Help Forum!
Quote:

Originally Posted by neils40
Find the equation of the circle which is tangential to the axis (2,0) and touches the line y=6

Unsure of workings?

Answers are; A, (x+2)^2 + (y-7)^2 = 26 B, 2x -y = 5 C, k = 0

Cheers Neils=)

The question that you've given us here doesn't make sense, and the answers don't correspond in any way. Can we see the original question please?

• July 21st 2009, 03:32 AM
neils40
Thanks Grandad.(Happy) That was form my text book, looks like a missprint maybe... I will as my teacher.
• July 21st 2009, 07:20 AM
HallsofIvy
Quote:

Originally Posted by neils40
Find the equation of the circle which is tangential to the axis (2,0) and touches the line y=6

Do you mean "tangent to the x-axis at (2,0)"? (2,0) is a point not a line.
If so, then both given tangent lines are horizontal and the center of the circle is at (2, 3).

Quote:

Unsure of workings?

Answers are; A, (x+2)^2 + (y-7)^2 = 26 B, 2x -y = 5 C, k = 0

Cheers Neils=)
There are no "A" or "B" in your question!
• July 21st 2009, 07:33 AM
Soroban
Hello, Neils!

Quote:

Find the equation of the circle tangent to the x-axis at (2,0) and tangent to the line y=6

$(A);\;(x+2)^2 + (y-7)^2 \:=\:26\qquad (B)\;\;2x -y \:=\:5 \qquad (C)\;\;k \,=\, 0$
          |       - - + - * * * - - - y=6           *          *         * |            *       *  |              *           |       *  |              *       *  |    o        *       *  |              *           |       *  |              *         * |            *           *          *     - - - + - * * * - - - - - -           |  (2,0)           |