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Math Help - Angle problem: Changing algebric expressions to angles

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    Angle problem: Changing algebric expressions to angles

    We prefer that the answers are defined in RR to the second power (I don't know what RR to the second power means). Answer graphically each answer in the same cartesian coordinate system.
    f(x)=2x
    h(x)=2x+2
    g(x)2x-1
    i(x)=2x-4
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    Quote Originally Posted by Julian.Ignacio View Post
    We prefer that the answers are defined in RR to the second power (I don't know what RR to the second power means). Answer graphically each answer in the same cartesian coordinate system.
    f(x)=2x
    h(x)=2x+2
    g(x)2x-1
    i(x)=2x-4
    This question is still not clear. Please state clearly what Changing algebric expressions to angles is meant to mean. Do you mean find the angle the line makes with the x-axis?
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    Yes...I'm sorry Mr.Fantastic, I study math in french so I gotta like translate some words which makes it hard for me to explain ;P, and yes an x-axis..sorry.
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    In a line y=mx+b, m=\tan \theta, \theta is the angle between the line and the positive direction of the x-axis.

    Here is a formula for you.

    Given that \theta is the angle formed from the line y=mx+b to line y=m'x+b', then

    \tan\theta=\frac {m'-m}{1+mm'}
    Last edited by chengbin; July 4th 2009 at 05:49 AM.
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    Quote Originally Posted by Julian.Ignacio View Post
    We prefer that the answers are defined in RR to the second power (I don't know what RR to the second power means). Answer graphically each answer in the same cartesian coordinate system.
    f(x)=2x
    h(x)=2x+2
    g(x)2x-1
    i(x)=2x-4
    The statement of that question is totally incomprehensible as far as I am concerned.
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  6. #6
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    Quote Originally Posted by chengbin View Post
    In a line y=mx+b, m=\tan \theta, where theta is the angle. Mr F adds: Between the line and the positive direction of the x-axis.

    Here is a formula for you.

    Given that \theta is the angle formed from the line y=mx+b to line y=m'x+b', then

    \tan\theta=\frac {m'-m}{1+mm'}
    ..
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