Thread: A geometric problem I am having issues with...

This is from an online worksheet. I cannot work this problem out.... Use the following diagram to answer the next two questions... Correct to the nearest tenth, the value of x is A. 5.2 B. 5.3 C. 5.4 D. 5.5 .................................................. .................................................. .................................................. ..... 2. Correct to the nearest half of a degree, the measure of angle ADB is: A. 30.5° B. 32.0° C. 34.5° D. 36.0° Thank you for the help!

Originally Posted by M23

This is from an online worksheet. I cannot work this problem out.... Use the following diagram to answer the next two questions... Correct to the nearest tenth, the value of x is A. 5.2 B. 5.3 C. 5.4 D. 5.5

Use Pythagorean theorem in RIGHT TRIANGLE PBC,

$\displaystyle PC^2=PB^2+BC^2
$

$\displaystyle PC^2=9^2+5^2$

PC=10.3

x = 10.3 - 5 = 5.3

Spoiler:

Pythagorean Theorem in Right Triangle

$\displaystyle a^2 = b^2+c^2$

$\displaystyle \Rightarrow(Hypotenuse)^2 = (first\;side)^2+(second \;side)^2$

Originally Posted by M23

This is from an online worksheet. I cannot work this problem out.... Use the following diagram to answer the next two questions... 2. Correct to the nearest half of a degree, the measure of angle ADB is: A. 30.5° B. 32.0° C. 34.5° D. 36.0° Thank you for the help!

IN Right triangle PBC,

$\displaystyle \tan P = \frac{5}{9}$

$\displaystyle P = 29.05^\circ$

$\displaystyle \angle C = 180 - 90 -29.05 = 60.95^\circ$

$\displaystyle \angle D = \frac{ 60.95}{2}=30.47=30.5^\circ$

Spoiler:

$\displaystyle \angle D = \frac{\angle C}{2}$

Thank you soooo much.