# Thread: A geometric problem I am having issues with...

1. ## A geometric problem I am having issues with...

This is from an online worksheet. I cannot work this problem out.... Use the following diagram to answer the next two questions... Correct to the nearest tenth, the value of x is A. 5.2 B. 5.3 C. 5.4 D. 5.5 .................................................. .................................................. .................................................. ..... 2. Correct to the nearest half of a degree, the measure of angle ADB is: A. 30.5° B. 32.0° C. 34.5° D. 36.0° Thank you for the help!

2. Originally Posted by M23
This is from an online worksheet. I cannot work this problem out.... Use the following diagram to answer the next two questions... Correct to the nearest tenth, the value of x is A. 5.2 B. 5.3 C. 5.4 D. 5.5
Use Pythagorean theorem in RIGHT TRIANGLE PBC,

$PC^2=PB^2+BC^2
$

$PC^2=9^2+5^2$

PC=10.3

x = 10.3 - 5 = 5.3

Spoiler:
Pythagorean Theorem in Right Triangle

$a^2 = b^2+c^2$

$\Rightarrow(Hypotenuse)^2 = (first\;side)^2+(second \;side)^2$

3. Originally Posted by M23
This is from an online worksheet. I cannot work this problem out.... Use the following diagram to answer the next two questions... 2. Correct to the nearest half of a degree, the measure of angle ADB is: A. 30.5° B. 32.0° C. 34.5° D. 36.0° Thank you for the help!
IN Right triangle PBC,

$\tan P = \frac{5}{9}$

$P = 29.05^\circ$

$\angle C = 180 - 90 -29.05 = 60.95^\circ$

$\angle D = \frac{ 60.95}{2}=30.47=30.5^\circ$

Spoiler:
$\angle D = \frac{\angle C}{2}$

4. Thank you soooo much.