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Math Help - Translation of axes

  1. #1
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    Translation of axes

    For the equation,find it's new equation if the origin is translated to the new origin as indicated.
    x^2+y^2-8x-10y+12    ; O(1,1)
    Attempt:
     x=x'+1 , y=y'+1
    (x+1)^2+(y+1)^2-8(x+1)-10(y+1)+12=0
     =x^2+y^2-6x-8y-4=0

    Am I correct ?
    Thank you
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  2. #2
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    Hello, mj.alawami!

    For the equation, find its new equation if the origin is translated to the new origin as indicated.

    x^2+y^2-8x-10y+12\:=\:0,\qquad O(1,1)
    Sorry, you are wrong . . .

    For horizontal and vertical translations, we use the opposite signs.

    . . \begin{array}{ccc}(0,0) &\to & (1,1) \\ \hline \\[-4mm] x &\to& x - 1 \\ y &\to& y - 1 \end{array}

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