# Thread: Cartesian eqn of a plane

1. ## Cartesian eqn of a plane

A plane passes through the P, with position vector i + 2j - k, and is perpendicular to the line L with eqn r = 3i -2k + w(-i + 2j + 3k)

Show that the Cartesian eqn of the plane is x - 5y -3z = -6

I'm not sure how to work out the normal of the plane?

2. Originally Posted by Erghhh
A plane passes through the P, with position vector i + 2j - k, and is perpendicular to the line L with eqn r = 3i -2k + w(-i + 2j + 3k)
Show that the Cartesian eqn of the plane is x - 5y -3z = -6
The answer I get is $x-2y-3z=0$.