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Math Help - Cartesian eqn of a plane

  1. #1
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    Cool Cartesian eqn of a plane

    A plane passes through the P, with position vector i + 2j - k, and is perpendicular to the line L with eqn r = 3i -2k + w(-i + 2j + 3k)

    Show that the Cartesian eqn of the plane is x - 5y -3z = -6

    I'm not sure how to work out the normal of the plane?
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  2. #2
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    Quote Originally Posted by Erghhh View Post
    A plane passes through the P, with position vector i + 2j - k, and is perpendicular to the line L with eqn r = 3i -2k + w(-i + 2j + 3k)
    Show that the Cartesian eqn of the plane is x - 5y -3z = -6
    Please check the details of your post.
    That given answer is answer is not perpendicular to the line L.
    The answer I get is x-2y-3z=0.
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  3. #3
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    Yeah, I was careful. It was from a past paper and I thought there was a typo. And on the mark scheme it says that the normal was 1i + 5j + 3k. I was skeptical about there being two typos on two separate documents. But I do agree with your answer.
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