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Math Help - Please help me on solving this problem

  1. #1
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    Please help me on solving this problem

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  2. #2
    Member javax's Avatar
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    For the first one use a^2+b^2=c^2
    in your case (\frac{6}{2})^2+d^2=5^2
    find d from here
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  3. #3
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    Each corner is a right isosceles triangle. Let the lengths of the legs each by s:
    \begin{aligned}<br />
s^2 + s^2 &= a^2 \\<br />
2s^2 &= a^2 \\<br />
s^2 &= \frac{a^2}{2} \\<br />
s &= \frac{a\sqrt{2}}{2}<br />
\end{aligned}
    (The above should look familiar. I did this in your other thread:http://www.mathhelpforum.com/math-he...eorem-2-a.html)

    The length of a side of the square, x, would be s + a + s:
    \begin{aligned}<br />
x &= s + a + s \\<br />
&= a + 2s \\<br />
&= a + 2\left(\frac{a\sqrt{2}}{2}\right) \\<br />
&= a + a\sqrt{2} \\<br />
&= a(1 + \sqrt{2})<br />
\end{aligned}


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