# Thread: Find Coordinates of Q

1. ## Find Coordinates of Q

I come across problems like this all the time. How does one find the coordinates of a given variable on a line segment when one point and the midpoint are given? What is the easiest way to do this?

Suppose that P is the endpoint of a segment PQ and M is the midpoint of PQ. Find the coordinates of Q.

P(7, -4), M(8,5)

2. Originally Posted by magentarita
I come across problems like this all the time. How does one find the coordinates of a given variable on a line segment when one point and the midpoint are given? What is the easiest way to do this?

Suppose that P is the endpoint of a segment PQ and M is the midpoint of PQ. Find the coordinates of Q.

P(7, -4), M(8,5)
just use the midpoint formula. plug in what you know, and solve for what you don't know.

Let $\displaystyle Q = (x,y)$

then, $\displaystyle \text{Midpoint (PQ)} = (8,5) = \left( \frac {x + 7}2, \frac {y - 4}2 \right)$

now equate the corresponding coordinates and solve for $\displaystyle x$ and $\displaystyle y$

3. ## Do you....

Originally Posted by Jhevon
just use the midpoint formula. plug in what you know, and solve for what you don't know.

Let $\displaystyle Q = (x,y)$

then, $\displaystyle \text{Midpoint (PQ)} = (8,5) = \left( \frac {x + 7}2, \frac {y - 4}2 \right)$

now equate the corresponding coordinates and solve for $\displaystyle x$ and $\displaystyle y$
Do you mean like this?

8 + 7/2 = y - 4/2

15/2 = y - 4/2

30 = 2y - 8

30 - 8 = 2y

22 = 2y

22/2 = y

11 = y

Now do the same for x?

Yes or no?

4. Originally Posted by magentarita
Do you mean like this?

8 + 7/2 = y - 4/2

15/2 = y - 4/2

30 = 2y - 8

30 - 8 = 2y

22 = 2y

22/2 = y

11 = y

Now do the same for x?

Yes or no?
no. i said equate corresponding components. that is, x-component with x-component and y-component with y-component

thus you have:

8 = (x + 7)/2

and

5 = (y - 4)/2

now you can find x and y

,

,

,

,

,

,

,

,

,

### solve this p(8,9)(8,7) pq dagya =?

Click on a term to search for related topics.