>>Coordinate Geometry: Find The Distance<<
yes im new so pls excuse if i do something wrong but,
I have an exam in eight hours and im panicking because im really tired.
Essentially, ive forgotten how to calculate distance in C/G (Coordinate Geometry) Puzzled with the first revision question already:
Find the distance between R(-1, 5) and S(2, -1)
the formula is:
Could someone please walk me through the process of working this out? thankyoou so much!
The booklet says:
The distance formula - geometry's great illusion
The distance formula is one of those equations which looks way more complicated than it is.
1) Forget coordinates for a second. What we are really looking at is the Pythagorean theorem:
We use this theorem to find the length of the hypotenuse in a right triangle. In order to use it, we need a length x and y between the two points you have.
2) So, lets get the length x and y. So the question here is, how far apart are the points (-1,5) and (2, -1) in the x and y direction? For x, we look at the x coordinates -1 and 2.
If these points are on a straight line, -1 and 2 are 3 units apart from one another or (2 - (-1)) = 3.
If the y coordinates are on a straight line, 5 and -1 are 6 units apart from one another or (5 - (-1)) = 6.
3) The distances 3 and 6 are our "a" and "b" values in the Pythagorean theorem. If you put all this mumbo-jumbo together you will get the "distance formula" that you found:
4) Simplifying, we get: