Hello, anonymous_maths!
In
is on such that:.
. . and is a point such that: .
Point is on so that
Show that: .
As you said, we have: . .[1]
Since
Substitute into [1]: .
. . Therefore: .
In the triangle OAB, OA = a and OB = b
The point P is the point on AB such that AP = 2PB and Q is a point such that OP = 3QP
Okay, this is a long question, I just couldn't do the last part.
The point R is on OA so that RQ is parallel to AB. Show that OR = 2/3 a (Hint: Let QR = cBA, where c is a scalar quantity)
I figured that OR = OQ + QR, and
OQ = 2/9 a + 4/9 b
now I am stuck.... any help will be appreciated. Thanks