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Math Help - Geometry problem.

  1. #1
    Newbie AknightwhosayNi's Avatar
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    Geometry problem.

    I been siting in one and a half hour trying to solve this problem, and i just can't do it. The picture is not exactly accurate, but i hope it will suffice. I really need help with this one. Please...

    M is the the center of the cirkle. Prove that the distance A-B has the same distance as the radius of the cirkle.
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  2. #2
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    Quote Originally Posted by AknightwhosayNi View Post
    M is the the center of the cirkle. Prove that the distance A-B has the same distance as the radius of the cirkle.
    You show that \Delta MAB is equilateral.
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  3. #3
    Newbie AknightwhosayNi's Avatar
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    Quote Originally Posted by Plato View Post
    You show that \Delta MAB is equilateral.
    How do I do that?
    I'm sorry, i'm not very good at math so i don't understand how to show that.
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  4. #4
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    Label the end points of the dominator E~\&~F.
    Then arc (EA)=60^o, arc (AB)=60^o, and arc (BF)=60^o.
    That tells us m\angle AMB = m\angle MBA = n\angle MAB = 60^o .
    That does it.
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  5. #5
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    circle


    The radius MB forms an angle of 30 with the chord BC. Then, angle ABM=60. The radius MA is the side of an isosceles triangle where another side is MB (they are both radius, that is, they are equal). And then angle MAB=60. That implies that angle AMB is also equal to 60 and the third side's lenght is equal to the radius
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