1. ## Geometry problem.

I been siting in one and a half hour trying to solve this problem, and i just can't do it. The picture is not exactly accurate, but i hope it will suffice. I really need help with this one. Please...

M is the the center of the cirkle. Prove that the distance A-B has the same distance as the radius of the cirkle.

2. Originally Posted by AknightwhosayNi
M is the the center of the cirkle. Prove that the distance A-B has the same distance as the radius of the cirkle.
You show that $\Delta MAB$ is equilateral.

3. Originally Posted by Plato
You show that $\Delta MAB$ is equilateral.
How do I do that?
I'm sorry, i'm not very good at math so i don't understand how to show that.

4. Label the end points of the dominator $E~\&~F$.
Then arc $(EA)=60^o$, arc $(AB)=60^o$, and arc $(BF)=60^o$.
That tells us $m\angle AMB = m\angle MBA = n\angle MAB = 60^o$.
That does it.

5. ## circle

The radius MB forms an angle of 30º with the chord BC. Then, angle ABM=60º. The radius MA is the side of an isosceles triangle where another side is MB (they are both radius, that is, they are equal). And then angle MAB=60. That implies that angle AMB is also equal to 60º and the third side's lenght is equal to the radius