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Math Help - Need lots of help! :D

  1. #1
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    Need lots of help! :D

    i need some help with my math homework. i don't know what to do

    heres question #1:

    A new rectangle with the word “STROM” is to be constructed inside the mat of an outside rectangle. The width of the mat surrounding the rectangular “STROM” logo will be the same. The area of the boundary around the word “STROM” will be the same as the logo itself. Determine the uniform width of the boundary.
    i made a picture of it including the measurements from the sheet:



    here's question #2:

    Staff and students at a school have been complaining about the location of the water fountains. You must decide if one or both fountains need to be relocated.
    Calculate the measure of angle 0, formed by the "line of sight" from the middle of the double doorway to the water fountains on the opposite wall.





    plz explain to me how I solve these step-by-step so I can understand it and learn from it for my quiz tomorrow, thanks!
    Last edited by brittney1993; June 1st 2009 at 02:29 PM.
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  2. #2
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    In the triangle if p = 302 inches, q = 237 inches and r = 465 inches , by using cosine rule you can find θ.
    r^2 = p^2 + q^2 -2pq*cosθ.
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  3. #3
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    Quote Originally Posted by brittney1993 View Post
    i need some help with my math homework. i don't know what to do

    heres question #1:

    i made a picture of it including the measurements from the sheet:



    plz explain to me how I solve these step-by-step so I can understand it and learn from it for my quiz tomorrow, thanks!
    The width of the border (call it "w") around the enclosed rectangle is to have the same area as the inside rectangle.

    Gross area:  294.5 \times 72 = A = the Total Area of the outside rectangle.

    The length of the inner rectangle is: 294.5 - 2w
    The width of the inner rectangle is 72 - 2w

    The area of the inner triangle is to be 1/2 the total or A/2

    Putting it together:

     (294.5 - 2w) (72-2w) = \frac{A}{2}

    Expanding the LHS

     294.5 \times 72 - 2w \times 72 - 2w \times 294.5 + 4w^2 = \frac{A}{2}

     294.5 \times 72 - 2w(72 + 294.5) + 4w^2 = \frac{A}{2}

    &

     4w^2 - 2(72 + 294.5)w + 294.5 \times 72 - \frac{294.5 \times 72}{2} = 0

    Use the quadratic formula and solve for x.



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