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- Dec 19th 2006, 03:47 PM #1

- Dec 19th 2006, 03:50 PM #2

- Dec 19th 2006, 03:51 PM #3

- Joined
- Apr 2006
- Posts
- 401

We know that the octagon has exactly 8 vertices. We are then able to create 5 diagonals from a given vertex.

8*5 = 40; however, there are some repeats. Each diagonal is counted twice since there are 2 points to each diagonal. Thus, 40/2 = 20 is the number of diagonals in a regular octagon.

- Dec 19th 2006, 03:55 PM #4