Hello, juvenilepunk!
This requires some trig.
Look at the circular cross-section . . .
Code:* * * * * * * * * * O * * * * * * |θ * 29.5 * * 9.5| * A*- - - - * - - - -*B *:::::::C:::::::* *:::::::::::* * * * D
The circle has radius inches.
The depth of the milk is 20 inches, so inches.
We want the area of segment
. . which is: .(area of sector ) - (area of triangle ).
In right triangle
. . Hence: .
And: .
in².
in².
Hence: . in².
The volume of the milk is: . in³.
Then: .