in the triangle ABC, AC=3, BC=2, angleBAC=theta and angleABC=2theta
calculate the value of theta to the nearest tenth of a degree.
i think i'm complicating this thing for myself because i cant get farther than 2 x sin2theta = 3 x sintheta
in the triangle ABC, AC=3, BC=2, angleBAC=theta and angleABC=2theta
calculate the value of theta to the nearest tenth of a degree.
i think i'm complicating this thing for myself because i cant get farther than 2 x sin2theta = 3 x sintheta
Hello the kopiteOK, so now carry on:
$\displaystyle 2\sin2\theta = 3\sin\theta$
$\displaystyle \Rightarrow 4\sin\theta\cos\theta = 3 \sin\theta$
$\displaystyle \Rightarrow \sin\theta = 0$ or $\displaystyle \cos\theta = \tfrac34$
$\displaystyle \Rightarrow \theta = 41.4^o$
Grandad