Please help me with this problem.

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- May 7th 2009, 02:29 AMlearnmath[SOLVED] Square Problem
Please help me with this problem.

- May 7th 2009, 06:10 AMSodapop
- May 7th 2009, 08:50 PMlearnmath
Yes, I can understand this part. Please help me with the other steps to arrive at the final answer.

- May 8th 2009, 01:32 AMrunning-gag
Hi

Consider triangle BPE. PR is one height of this triangle. The area of BPE is

The same for triangle BPC :

The area of triangle BCE is the sum of the areas above :

Since BE = BC,

On the other hand the area of triangle BCE can be calculated using the projection of E on [BC], say H

Since ABCDE is a square, angle CBE is 45 degrees. Therefore

Hence

And finally - May 10th 2009, 07:27 PMlearnmath
Thank you!