The dimensions of a rectangular box are sqrt{2}, sqrt{3} and 4(sqrt{6}). Find volume in simplest radical form. I found the volume to be 24 but is 24 in simplest radical form?
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Yes it is, because: = sqrt{2} * sqrt{3} * 4(sqrt{6}) = 4(sqrt{36}) Then the simpler form is 4(6), because you're reducing just like you would a fraction, such as the simplest form of 81/3 being 27, or 3^3. So, 24 would be the simplest form.
Originally Posted by magentarita The dimensions of a rectangular box are sqrt{2}, sqrt{3} and 4(sqrt{6}). Find volume in simplest radical form. I found the volume to be 24 but is 24 in simplest radical form? Note that the volume is actually $\displaystyle 24\textrm{ units}^3$
Originally Posted by Prove It Note that the volume is actually $\displaystyle 24\textrm{ units}^3$ Sorry. Just thought it was assumed. And thanks for showing me how to use "textrm" to format my writing!
Originally Posted by Prove It Note that the volume is actually $\displaystyle 24\textrm{ units}^3$ Yes, I forgot that volume in measured in cubic units.
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