# Rectangular Box

• May 5th 2009, 09:14 PM
magentarita
Rectangular Box
The dimensions of a rectangular box are sqrt{2}, sqrt{3} and 4(sqrt{6}). Find volume in simplest radical form.

I found the volume to be 24 but is 24 in simplest radical form?
• May 5th 2009, 09:51 PM
dunafrothint
Yes it is, because:

= sqrt{2} * sqrt{3} * 4(sqrt{6})
= 4(sqrt{36})

Then the simpler form is 4(6), because you're reducing just like you would a fraction, such as the simplest form of 81/3 being 27, or 3^3. So, 24 would be the simplest form.
• May 5th 2009, 09:55 PM
Prove It
Quote:

Originally Posted by magentarita
The dimensions of a rectangular box are sqrt{2}, sqrt{3} and 4(sqrt{6}). Find volume in simplest radical form.

I found the volume to be 24 but is 24 in simplest radical form?

Note that the volume is actually

$24\textrm{ units}^3$
• May 5th 2009, 10:00 PM
dunafrothint
Quote:

Originally Posted by Prove It
Note that the volume is actually

$24\textrm{ units}^3$

Sorry. Just thought it was assumed. And thanks for showing me how to use "textrm" to format my writing!
• May 6th 2009, 05:13 AM
magentarita
Thanks
Quote:

Originally Posted by Prove It
Note that the volume is actually

$24\textrm{ units}^3$

Yes, I forgot that volume in measured in cubic units.