Hello, Ash!
If CD = 15, what is the length of AE?Code:A * |* | * | * | * | * | * | 10 * E *-------*B | |* 10| 10| * | | * D *-------*---* C 10 F 5
Since CD = 15 and DF = 10, then FC = 5.
Triangle AEB is similar to triangle BFC.
. . . . . . . . . . AE . .BF . . . . . AE . .10
So we have: . --- = --- . --> . --- = ---
. . . . . . . . . . EB . .FC . . . . . 10 . . 5
Therefore: .AE = 20