I need help urgently on how to solve these problems I am extremely confused :
(I think that 1 a) 100 but I can't figure out how to get the other ones.)
Thank you very much for the help with #1. After re-reading and reading #1's explanation I came up with these answers for #2 :
c) 80 or 100? ( this is the one that confused me)
Originally Posted by Geometric
I have a problem with only two of your answers.
(c) because angle CPT is supplementary to angle CPB. Now we know that in triangle CBP, angle ACB is 80 degrees. We found that using the proportions. Angle CBP is 30 degrees because angle CBA was found to be 60 degrees using the proportions, and according to the given, it is bisected by BT. So, in triangle CBP, we have angles of 30 and 80 degrees. That leaves angle CPB to be 70 degrees. Angle CPT is supplementary to angle CPB because they make up a linear pair.
(e) because it is one-half the difference of the intercepted arc measues on the circle. This angle intercepts arc AX (not labeled in diagram) and arc AB. Arc AX measues 60 degrees because the intercepted angle ABP = 30 degrees. Arc AB measures 160 degrees since its inscribed angle ACB measures 80 degees. So, angle T = 1/2(160 - 60) = 50 degrees.
Thank you very much for your help!