In a quadrilateral ABCD, AB produced is perpendicular to DC produced.
If A = 44 and C = 148, calculate D and B.

2. Originally Posted by hi00000
In a quadrilateral ABCD, AB produced is perpendicular to DC produced.
If A = 44 and C = 148, calculate D and B.

Is it looks like this?

What are the meanings of A=44 and C=148?

3. ## Angles

Hello hi00000
Originally Posted by hi00000
In a quadrilateral ABCD, AB produced is perpendicular to DC produced.
If A = 44 and C = 148, calculate D and B.
Suppose that $AB$ and $DC$ produced meet at $E$. Then in $\triangle ADE, A=44^o, E= 90^o \Rightarrow D=46^o$

In $\triangle BCE, B=180-148=32^o \Rightarrow C = 58^o$. So in the quadrilateral $ABCD, C = 180-58 = 22^o$.