In a quadrilateral ABCD, AB produced is perpendicular to DC produced.
If A = 44 and C = 148, calculate D and B.
Hello hi00000Suppose that $\displaystyle AB$ and $\displaystyle DC$ produced meet at $\displaystyle E$. Then in $\displaystyle \triangle ADE, A=44^o, E= 90^o \Rightarrow D=46^o$
In $\displaystyle \triangle BCE, B=180-148=32^o \Rightarrow C = 58^o$. So in the quadrilateral $\displaystyle ABCD, C = 180-58 = 22^o$.
Grandad