If the circumference of a circle is 4*pi/3, then what is half of its area?
a 2*pi/9
b.4*pi/9
c.8*pi/9
d.2*pi squared/9
$\displaystyle 2\pi r=\frac{4\pi}{3}$
Divide by $\displaystyle \pi$ to get,
$\displaystyle 2 r=4/3$
Divide by 2,
$\displaystyle r=2/3$.
Thus,
$\displaystyle A=\pi (2/3)^2=(16/9)\pi$
Half of that is,
$\displaystyle (8/9)\pi$