hi i have no idea where to start on this.
please could somebody explain
find the slope on the line tangent to the curve
y = (x^3 -1)(x^2+3x+2) at the point (1,0)
Sorry craigm, I did not actually find the derivative to your function
Your Equation
Should be expanded to give
Using differentiation to help find the gradient (or tangent) with respect to x
now substitute x = 1 into this equation! This should yield 18.
My method is a little more primative to that supplied by the previous poster (thanks for the correction!) but my method is great if you have not been introduced to the product rule