hi i have no idea where to start on this.

please could somebody explain

find the slope on the line tangent to the curve

y = (x^3 -1)(x^2+3x+2) at the point (1,0)

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- Apr 20th 2009, 04:23 PMcraigmfind the slope of the curve:
hi i have no idea where to start on this.

please could somebody explain

find the slope on the line tangent to the curve

y = (x^3 -1)(x^2+3x+2) at the point (1,0) - Apr 20th 2009, 06:42 PMpickslides
- Apr 20th 2009, 06:50 PMTheEmptySet
- Apr 20th 2009, 06:59 PMpickslides
Sorry craigm, I did not actually find the derivative to your function

Your Equation

Should be expanded to give

Using differentiation to help find the gradient (or tangent) with respect to x

now substitute x = 1 into this equation! This should yield 18.

My method is a little more primative to that supplied by the previous poster (thanks for the correction!) but my method is great if you have not been introduced to the product rule