File attached. I'm not too sure how to do this, here's what I have so far:
BP = PC (tangents that cross coming from a circle) [side]
angle ACX = angle ABC (alternate segments)
angle YBA = angle ACD (alternate angles)
Therefore, angle ABC = ACB
File attached. I'm not too sure how to do this, here's what I have so far:
BP = PC (tangents that cross coming from a circle) [side]
angle ACX = angle ABC (alternate segments)
angle YBA = angle ACD (alternate angles)
Therefore, angle ABC = ACB
Hi GAdams,
Prove
- Given
are tangent to the circle - Given
- If two angles of a triangle are congruent, then the sides opposite these angles are congruent.
- If two segments from the same exterior point are tangent to a circle, then they are congruent.
- Reflexive property of congruence.
- SSS Postulate