File attached. I'm not too sure how to do this, here's what I have so far:

BP = PC (tangents that cross coming from a circle) [side]

angle ACX = angle ABC (alternate segments)

angle YBA = angle ACD (alternate angles)

Therefore, angle ABC = ACB

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- Apr 20th 2009, 10:14 AMGAdamsProving Congruence
File attached. I'm not too sure how to do this, here's what I have so far:

BP = PC (tangents that cross coming from a circle) [side]

angle ACX = angle ABC (alternate segments)

angle YBA = angle ACD (alternate angles)

Therefore, angle ABC = ACB - Apr 20th 2009, 10:35 AMmasters
Hi GAdams,

Prove

- Given

are tangent to the circle - Given

- If two angles of a triangle are congruent, then the sides opposite these angles are congruent.

- If two segments from the same exterior point are tangent to a circle, then they are congruent.

- Reflexive property of congruence.

- SSS Postulate - Apr 20th 2009, 11:03 AMGAdams
than you!

Not sure how to find angle ABC...

I can see that angle BPA and angle CPA are the same - Apr 20th 2009, 01:51 PMmasters