I don't know how to do this question, could someone please explain?
Hello, iamanoobatmath!
I hope you can follow my labelling.
(I couldn't make a diagram of this one!)
The vertex of the angle is $\displaystyle A.$
Draw a line from $\displaystyle A$ through the centers of the circles.
It first intersects the small circle at $\displaystyle B$,
the center of the smaller circle is $\displaystyle C$,
$\displaystyle D$ is the point of tangency of the two circles,
the center of the larger circle is $\displaystyle E$.
From C, draw a radius down to the point of tangency, $\displaystyle F.$
From E, draw a radius down to the point of tangency, $\displaystyle G.$
We have: .$\displaystyle BC = CD = CF = 8$
Let $\displaystyle DE = EG = r$
In right triangle $\displaystyle CFA,\;\angle CAF = 30^o\,\text{ and }\,CF = 8.$
. . Hence, the hypotenuse $\displaystyle AC = 16.$
Since $\displaystyle \Delta EGA \sim \Delta CFA$, we have: .$\displaystyle \frac{EG}{EA} \:=\:\frac{CF}{CA}$
. . That is: .$\displaystyle \frac{r}{r+24} \:=\:\frac{8}{16} \quad\Rightarrow\quad r \:=\:24$
Therefore, the circumference of the larger circle is: .$\displaystyle 48\pi$ cm.