Find the area described by

$\displaystyle x+y+z=L$ and $\displaystyle 0<x,y,z<\frac{L}{2}$

Is this the SAME area as $\displaystyle x+y+z = \frac{L}{2}$ and $\displaystyle x,y,z>0$?

Thanks~!

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- Apr 12th 2009, 09:03 AMDivideBy0Area in 3D plane graph
Find the area described by

$\displaystyle x+y+z=L$ and $\displaystyle 0<x,y,z<\frac{L}{2}$

Is this the SAME area as $\displaystyle x+y+z = \frac{L}{2}$ and $\displaystyle x,y,z>0$?

Thanks~! - Apr 12th 2009, 10:26 AMwytiaz
The first equation is off. x+y+z will be less than 3L/2 but not necessarily less than L/2