Is "the image of a point with respect to a line" the "location of the point after reflection across the line"?

If so, then find the slope of the line 4x + 3y + 6 = 0 (bysolving for "y="and then reading off the value of "m").Find the equationof the line through (1, 5) and havinga slope that is perpendicular tothe original line.

Now that you have two line equations, you have a system of equations.Solve this systemto find where the two lines cross. The intersection point is the closes point on the line to the point (1, 5).

Plug the original point and the intersection point intothe Midpoint Formula, using (x, y) as the point equidistant on the other side, and solve for the coordinates of the image (mirrored) point.

You might find it simplest to mirror a few points from y = 2x - 1 first (since you'll just be swapping the x- and y-values for the mirrored line), and then pick two of those points and find the equation of the line through them.

If you get stuck, please reply showing all of your steps and reasoning so far. Thank you!