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  1. #1
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    Equation of the chord of the circle x^2+y^2-4x=0 whose mid point is (1,0) is?
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  2. #2
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    Quote Originally Posted by cnpranav View Post
    Equation of the chord of the circle x^2+y^2-4x=0 whose mid point is (1,0) is?
    1. The circle has the center C(2, 0) and the radius r = 2.

    2. If the point M(1, 0) is the midpoint of the chord then the x-axis must be the bisector of the chord.

    3. For symmetry reasons the equation of the chord is x = 1
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    Thanks buddy
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