Equation of the chord of the circle x^2+y^2-4x=0 whose mid point is (1,0) is?

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Originally Posted by cnpranav Equation of the chord of the circle x^2+y^2-4x=0 whose mid point is (1,0) is? 1. The circle has the center C(2, 0) and the radius r = 2. 2. If the point M(1, 0) is the midpoint of the chord then the x-axis must be the bisector of the chord. 3. For symmetry reasons the equation of the chord is x = 1

Thanks buddy