please tell me how to solve this problem

The ratio of the area of square to that of the square drawn on its diagonal is:

(A)1:3

(B)3:4

(C)2:3

(D)1:2

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- April 3rd 2009, 06:46 AMrickymylvArea of square
please tell me how to solve this problem

The ratio of the area of square to that of the square drawn on its diagonal is:

(**A**)1:3

(**B**)3:4

(**C**)2:3

(**D**)1:2 - April 3rd 2009, 06:51 AMADARSH
- April 3rd 2009, 07:28 AMChop Suey
Given a square with sides of length s, the length of the diagonal of the square is equal to

The question asks for the ratio of the area of a square to the area of a square drawn on its diagonal. As in:

- April 3rd 2009, 07:35 AMSoroban
Hello, rickymylv!

Quote:

Please tell me how to solve this problem

The ratio of the area of a square to that of the square drawn on its diagonal is:

. .

Code:`* - - - - - *`

| |

| |

| | s

| |

| |

* - - - - - *

s

Code:`* - - - - - *`

| _ * |

| √2s * |

| * | s

| * |

| * |

* - - - - - *

s

. .

The area of the square of side is: .

Therefore, the ratio of the two areas is . . .

- April 3rd 2009, 09:35 AMlebanonhello
let the side of the square be (a),so the area of the first square is a^2,

then by pythegoras , it's diagonal is a√2,and the area of the second square ia (a√2)^2=2(a^2).

therefore the ratio is:a^2 / 2(a^2)=1/2

D is correct.