THere are given lines p1:$\displaystyle \left( {m - 6} \right)x + \left( {m - 1} \right)y + 13 = 0$ and p2:$\displaystyle \left( {2m + 1} \right)x + 3my - 9 = 0$

Determine $\displaystyle m$ so that lines p1 and p2 have one common pointFandFis a point of this line q:$\displaystyle 2x+y-5$