Given:
Sides AB and BC of triangle ABC, extended, are tangent to a circle at points D and E, and side BC is tangent at F.
If AB = 8, AC = 9, and CF = 2, find BF.
My Work So Far:
* I can see that BF = x and there are 2 x's, so if I connect point D to F, triangle BDF will be isosceles. But I don't really see how that will help me find the length I need.
* Can I set up a proportion such that 8 : 2 = 9 : x?
So x = 3 = BF?
I'm stuck


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